If X1 and X2 are the two real roots of the equation x ^ 2 - (2k + 1) x + K ^ 2 + 1 = 0 about X, and X1 and X2 are greater than 1

If X1 and X2 are the two real roots of the equation x ^ 2 - (2k + 1) x + K ^ 2 + 1 = 0 about X, and X1 and X2 are greater than 1

(1) Discriminant = 4k-3 > = 0 K > = 3 / 4 Veda theorem X1 + x2 = 2K + 1 > 2K > 0.5 x1x1 = k ^ 2 + 1 > 1 K is not equal to 0 because a > 0, when x = 1, Y > 0 K is not equal to 1. In conclusion, K > = 3 / 4 and K is not equal to 1 (2), let X1 = a, then x2 = 2A, the original equation = (x-a) (x-2a) = 0