Given that point a (0, - 1) and point B are moving points on the curve X ^ 2-y ^ 2 + X + 2Y + 3 = 0, then the trajectory equation of the midpoint of line AB is obtained

Given that point a (0, - 1) and point B are moving points on the curve X ^ 2-y ^ 2 + X + 2Y + 3 = 0, then the trajectory equation of the midpoint of line AB is obtained

Let B (a, b), then a ^ 2-B ^ 2 + A + 2B + 3 = 0
The midpoint of AB (A / 2, (B-1) / 2)
x=a/2---> a=2x
y=(b-1)/2---> b=2y+1
Substituting a and B into the above formula, we can get 2x ^ 2 - (4Y ^ 2 + 4Y + 1) + 2x + 4Y + 2 + 3 = 0
The simplified trajectory equation is: x ^ 2-2y ^ 2 + X + 2 = 0

Elden Ring Premiere

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