X ^ 2 + y ^ 2 + 6x + 8y + 25 = 0, find the value of (x ^ 2) - (Y ^ 2)
∵x^2+y^2+6x+8y+25=0
Formula:
(x+3)²+(y+4)²=0
Ψ x + 3 = 0 and y + 4 = 0
∴x=-3,y=-4
∴x²-y²=9-16=-7
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