Given the function f (x ^ 2-3) = logx ^ 2 / x ^ 2-6, find the definition field of F (x)

f(x^2-3)=logx^2/(x^2-6)
=log(x^2-3+3)/(x^2-3-3)
So f (x) = log (x + 3) / (x-3)
The true number is greater than 0
(x+3)/(x-3)>0
(x+3)(x-3)>0
x3
So domain
(-∞,-3)∪(3,+∞)

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