Y = log [(1 / 3) ^ 2] x + 2log (1 / 3) x + 3 when 1 / 27 is less than or equal to X and less than or equal to 9, find the maximum and minimum value of the function

First of all, log [(1 / 3) ^ 2)] x = 2log (1 / 3) X. This doesn't need to be explained. It's a logarithmic power operation
y=4log1/3x+3 1/27

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