Let x 1x 2 be a quadratic equation of one variable with respect to X. x (square) - 2 (m-1) x + m + 1 = 0. Two real roots are obtained. Y = x 1 + x 2 (both have squares). The analytic trial and range of y = f (m) are obtained

Let x 1x 2 be a quadratic equation of one variable with respect to X. x (square) - 2 (m-1) x + m + 1 = 0. Two real roots are obtained. Y = x 1 + x 2 (both have squares). The analytic trial and range of y = f (m) are obtained

x1+x2=2(m-1)
x1*x2=m+1
y=x1^2+x2^2
=(x1+x2)^2-2x1x2
=4(m-1)^2-2(m+1)
=4m^2-10m+2
There are two real roots
So 4 (m-1) ^ 2-4 (M + 1) > = 0
4m^2-12m>=0
m>=3,m

Elden Ring Premiere

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