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Given the function f (x) = x2-4, if f (- m2-m-1) < f (3), then the value range of real number m is () A. （-2，2）B. （-1，2）C. （-2，1）D. （-1，1）
From the properties of quadratic function, it can be concluded that the symmetry axis of F (x) = x2-4 is y-axis, the even function ∵ f (x) increases monotonically on (0, + ∞) and decreases monotonically on (- ∞, 0). From the solution of F (- m2-m-1) < f (3), we can get - m2-m-1 is closer to Y-axis than 3, that is | - m2-m-1 | < | 3 | - 3 | - M2 + m + 1 < 3, that is M2 + m − 2 < 0m2 + m + 4 > 0, so we choose C < m < 1
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