If the even function f (x) defined on R has f (x2) - f (x2) / x2-x1 < 0 for any X1 x2 ∈ [0, + ∞) (x1 is not equal to x2), then a f (3) < f (- 2) < f (1) B F (1) < f (- 2) < f (3) C f (- 2) < f (1) < f (3) d f (3) < f (1) < f (- 2)
From [f (x2) - f (x2)] / (x2-x1) < 0, we know that on [0, + ∞), f (x) decreases monotonically;
And f (x) is even function, so f (x) increases monotonically on (- ∞, 0]
Because f (- 2) = f (2), and 0
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