Derivative of implicit function x + y-e ^ x * y = 0
x+y-e^x*y=0
If both sides take derivatives of X at the same time, we get the following result
1+y'-e^(xy)*(y+xy')=0
(1-xe^(xy))y'=e^(xy)-1
y'=[e^(xy)-1]/[1-xe^(xy)]
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