X = 3E ^ (- t), y = 2E ^ t, find the second derivative of the parametric equation

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• 1. Find the derivative of the function y determined by the parametric equation {x = 1-T ^ 2, y = T-T ^ 3}
• 2. Find the first derivative of the function determined by the parametric equation {x = T-1 / T + 1, y = T & # / 1 + T} The answer I made is T & # + 2T / 2. I did this n times, but it's not the same as the answer,
• 3. The derivative of the function y = 4x ^ 2 + 1 / X is Is the derivative of 1 / X - 1?
• 4. For a project, Party A and Party B cooperate to complete five sixths of the project in six days. If they do it alone, it will take party a one-third of the time to complete and Party B one-half of the time to complete
• 5. 5.5x-1.3x=12.6                 3.85+1.5x=6.16x-0.9=4.5                    4×4.5-3x=6.33．
• 6. For a batch of goods, two fifths of them were transported in the first time, and 75 kg in the second time. A total of 65% of the total amount was transported in the two times. How many kg are there in total?
• 7. The image of linear function y = KX + B passes through (- 2,5) and intersects with y axis on P line, y = - X / 2 + 3 intersects with y, and O P.O is symmetric about X axis The expression of this function
• 8. There are 60 male workers in a workshop, one third more than female workers. How many female workers are there
• 9. Mathematical problems of derivative function, How to understand that the tangent equation of a given curve y = f (x) at x = 1 is y = X-1, Analysis shows that, f (1) = 0, f '(1) = 1,? This place does not understand, what is the relationship between the derivative function of the curve and the tangent, why f' (1) = 1, find the reasoning process
• 10. There are 200 sixth grade students, half of whom are boys, equal to one third of whom are girls. How many boys and girls are there in the sixth grade Why 2 + 3
• 11. The derivative of an implicit function is known and the implicit function is solved Given (y-2xy) DX + x2dy = 0, when x = 1, y = E; find y = f (x) 2 in x2dy is the square of X
• 12. Finding the second derivative of implicit function (y ^ 2) x = e ^ (Y / x)
• 13. Finding the derivative of implicit function y = y (x) determined by e ^ y = cos (x + y)
• 14. Derivative of implicit function x + y-e ^ x * y = 0
• 15. Finding the derivative of the implicit function y = y (x) determined by y = x + LNY
• 16. Finding the derivative of implicit function y to X Y ^ 2-3xy + 9 = 0 requires steps
• 17. On the derivative of implicit function X ^ 2 + y ^ 2 = 25 derivative: 2x + 2yy '= 0 question: why is the derivative of x ^ 2 2x and the derivative of Y ^ 2 2yy'? Although the examples in the book are all solved in this way, I still don't understand. Please help me explain it. Thank you
• 18. How to find the derivative of implicit function? For the derivative of the implicit function e ^ y + xy-e = 0, both sides of the equation derive from X: D / DX (e ^ y + xy-e) = e ^ y (dy / DX) + y + X (dy / DX). Why is x (dy / DX) derived from e? Shouldn't it be 0? There is another derivative from y ^ 2-2xy + 9 = 0: 2yy '- 2Y + 2XY' = 0? Why does 9 become 2XY '? Where do you get 2XY' from? I don't understand```````````````
• 19. Find the derivative of this implicit function Let y = sin (x + y), x = π, find y ' The answer in this book is - 1 / 2, how to calculate Let y = sin (x + y) determine the implicit function y = y (x), then dy = (2) How did this "2" come from? Can we do that? Y = sin (π + y) → y = - Sin y → derivation on both sides y '= - y'cosy reduces y' to cosy = - 1, but in this way, y '= cos (x + y) * (1 + y') = cos (π + y) * (1 + y ') = - cosy * (1 + y') is sorted out and y '= - cosy / (1 + cosy) is substituted into cosy = - 1, and the result is y' = 1 / O. what's wrong with this process?
• 20. Let f (x) = e ^ x-1-x-ax ^ 2 (1) if a = 0, find the monotone interval of F (x). (2) if x is greater than or equal to 0, f (x) is greater than or equal to 0 Thank you for your help Thank you for the process