Given that the sum of odd and even terms of the arithmetic sequence {an} with even terms is 51, 60, and the first term is 1, then the general term formula of the sequence is obtained
Suppose that the arithmetic sequence {an} has 2m items and the tolerance is D, then a1 + a3 + +a[2m-1]=51 (1)a2+a4+… +A [2m] = 60 (2) from (1), we get (a1 + a [2m-1]) m / 2 = 51 ∵ a [2m-1] = a1 + (2m-2) d = 1 - (2m-2) d ∵ [1 + 1 + (2m-2) D] m / 2 = 51, namely [1 + (m-1) D] m = 51 (3) (2) - (1), we get (a2-a1) + (a4-a3) +