BN = 1 / (2n-1) (2n) sum

Let 1 / [(2n-1) (2n)] = - 1 / (2n) + 1 / (2n-1)
b1= -1/2 + 1/1
b2= -1/4 + 1/3
b3= -1/6 + 1/5
b4= -1/8 + 1/7
No solution. Is the title written wrong?

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