Given a + B-8A + 6B + 25 = 0, find the value of a + ab-6 of a-4ab + 4B

From (a ^ - 8A + 16) + (b ^ + 6B + 9) = 0
(a-4)^+(b+3)^=0
We get a = 4, B = - 3
Substitute the value into (a ^ + ab-6 ^) / (a ^ - 4AB + 4B ^)
It is (- 32) / (a-2b)^
(-32)/100=-(8/25)

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