Given a + B-8A + 6B + 25 = 0, find the value of a + ab-6 of a-4ab + 4b, and the value of a + ab-6 of a + 4B How can elder martial brothers and sisters help My problem will be taught tomorrow!

Given a + B-8A + 6B + 25 = 0, find the value of a + ab-6 of a-4ab + 4b, and the value of a + ab-6 of a + 4B How can elder martial brothers and sisters help My problem will be taught tomorrow!

A is represented by a ^ 2
The known condition is a ^ 2 + B ^ 2-8a + 6B + 25 = 0
It can be written as a ^ 2-8a + 16 + B ^ 2 + 6B + 9 = 0
That is, (A-4) ^ 2 + (B + 3) ^ 2 = 0;
So a = 4, B = - 3
Finally, the required formula is a little incomprehensible. Maybe it can be factorized, but I can calculate the value of a and B