A natural number has 16 divisors, and this number can't be divided by 3, 5, and 8. What's the minimum of this natural number?

A natural number has 16 divisors, and this number can't be divided by 3, 5, and 8. What's the minimum of this natural number?

The minimum value is 2002 = 2 × 7 × 11 × 13. For a natural number m, let it be expressed as M = B1 power of A1 × B2 power of A2 Then the divisor of M is (B1 + 1) × (B2 + 1) × (B3 + 1) × ×(bn...