The natural numbers that can be divided by both 5 and 7 are arranged in a column from small to large from 35. What is the remainder of the sum of the first 1994 numbers in this column divided by 11 It must be solved by arithmetic One line, one formula Neat and easy to understand There is a small mark with a small mark

The least common multiple of 5 and 7 is 35, so the natural number that can be divided by 5 and 7 is the sum of the first 1994 numbers of 35 * 1, 35 * 2,..., 35 * 1994,... S = 35 * (1 + 2 +... + 1994) = 35 * (1 + 1994) * 1994 / 2 = 35 * 1995 * 997 = 69615525 (9 + 1 + 5 + 5) - (...)

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