What is the sum of the first 100 positive natural numbers divisible by 3

What is the sum of the first 100 positive natural numbers divisible by 3

3 (1 + 2 + 3 +... + 32 + 33) = 3 * (1 + 33) * 33 / 2 = 3 * 34 * 33 / 2 = 3 * 33 * 17 = (100-1) * 17 = 1700-17 = 1683. Let s = 1 + 2 + 3 +... + 31 + 32 + 33, then s = 33 + 32 + 31 +... + 3 + 2 + 12s = (1 + 33) + (2 + 32) + (3 + 31) +... (31 +...)