How to factorize 3 (square of M) minus 8MN minus 12 (square of n)

3m^2-8mn-12n^2=3(m^2-8mn/3+16n^2/9-16n^2/9)-12n^2=3(m-4n/3)^2-52n^2/3=3[(m-4n/3)^2-52n^2/9]=3[(m-4n/3+2√13n/3)(m-4n/3-2√13n/3)]=(1/3)(3m-4n+2√13n)(3m-4n-2√13n)

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1. Decomposition factors: (1) A2 + b2-2ab-1; (2) (2x + y) 2 - (x-2y) 2; (3) (a + b) 2-6 (a + b) + 9; (4) - 4 (M + n) 2 + 25 (m-2n) 2
2. 12 / 4 of the square of M = 3 / 2 of M
3. Square of M + 4m-12 = 0
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