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The quadratic function f (x) satisfies f (2 + x) = f (2-x), f (2) = 1, f (0) = 3. If f (x) has a minimum value of 1 and a maximum value of 3 on [0, M], then the value range of M is
Because the quadratic function f (x) satisfies f (2 + x) = f (2-x)
So the quadratic function takes x = 2 as the axis of symmetry
So f (2) = 1 is the minimum value of the function
Because f (0) = 3, f (4) = 3
Draw a picture to see 2
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