Given that the square of M = 2n + 4, the square of (2n) is m + 1, evaluate: (1) m + 2n; (2) the third power of 4N - the square of Mn + 2n Evaluation can only have numbers

Given that the square of M = 2n + 4, the square of (2n) is m + 1, evaluate: (1) m + 2n; (2) the third power of 4N - the square of Mn + 2n Evaluation can only have numbers

（1）m^2=2n+1
4n^2=m+1
The subtraction of the two formulas is: m ^ 2-4n ^ 2 = 2n-m
And because m ^ 2-4n ^ 2 = (M + 2n) (m-2n) = 2n-m
So m + 2n = - 1
（2）（2n）^2=m+1
Then 4N ^ 3 = n (M + 1) = Mn + n
That is 4N ^ 3-Mn = n
And 4N ^ 2 = (M + 1)
So 2n ^ 2 = (M + 1) / 2
4n^3-mn+2n^2
=(4n^3-mn)+2n^2
=n+(m+1)/2
=(2n + m + 1) / 2. (because m + 2n = - 1)
=(-1+1)/2
=0