Given a & 2 + B & 2 + C & 2-ab-3b-2c + 4 = 0, find the value of a + B + C

a²+b²+c²-ab-3b-2c+4=0
The formula is (a-b / 2) & sup2; + (C-1) & sup2; + 3 (B / 2-1) & sup2; = 0
So,
a-b/2=0
c-1=0
b/2-1=0
a=1,b=2,c=1
a+b+c=1+2+1=4

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