Given that the three sides of triangle ABC are a, B, C respectively, and the area is s = (a ^ 2 + B ^ 2-C ^ 2) / 4, find Sina + cosa

Given that the three sides of triangle ABC are a, B, C respectively, and the area is s = (a ^ 2 + B ^ 2-C ^ 2) / 4, find Sina + cosa

S = (a ^ 2 + B ^ 2-C ^ 2) / 4 cosine theorem
=1/2abcosC
s=1/2absinC C=45