If A.B.C is trilateral of △ ABC, and A.B satisfies the relation (A-3) &# 178; + [B-4 \ = 0, C is a system of inequalities {X-1 / 3 ＞ x-4, {2x + 3 ＜ 6x + 1 / 2} (Continued) to find the three sides of △ ABC By 22:40 today,

First of all, the equation: if both positive numbers are added and equal to 0, then both numbers must be 0. So a = 3, B = 4
All real numbers can be obtained by solving the inequality X - 1 / 3 > x - 4
All numbers larger than 5 / 8 can be obtained by solving 2x + 3 ＜ 6x + 1 / 2 inequality X
So C is all numbers greater than 5 / 8. We can't find out the value of C

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