If the three sides of △ ABC are a, B, C, and its area is ᦉ 188; (a ᦉ 178; + B ᦉ 178; - C ᦉ 178;), then what is the internal angle c?
According to the meaning of the title:
1/2absinC=1/4(a²+b²-c²)
According to the cosine theorem, COSC = (a ^ 2 + B ^ 2-C ^ 2) / (2Ab)
So sinc = COSC
C is 45 degrees
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