Acute angle △ ABC. Known (b ^ + C ^ - A ^) Tana = √ 3bC 1) find angle a (2) if a = 2, find ∠ a

Acute angle △ ABC. Known (b ^ + C ^ - A ^) Tana = √ 3bC 1) find angle a (2) if a = 2, find ∠ a

The first question is as follows: (b ^ 2 + C ^ 2-A ^ 2) Tana = √ 3bC,
By substituting the cosine theorem B ^ 2 + C ^ 2-A ^ 2 = 2bccosa, 2bcsina = √ 3bC,
That is, Sina = √ 3 / 2 shows that a = 60 degree
The second question of the title, is there a problem? Didn't a find out?