In the rectangular coordinate system, there are four points a (- 6, - 3), B (- 2, - 5), C (0, m), D (n, 0). When the perimeter of the quadrilateral ABCD is the shortest, the values of M and N can be obtained

In the rectangular coordinate system, there are four points a (- 6, - 3), B (- 2, - 5), C (0, m), D (n, 0). When the perimeter of the quadrilateral ABCD is the shortest, the values of M and N can be obtained

In short, it is to find out the points c, D and a, which are symmetrical to the x-axis. A1 and B, which are symmetrical to the y-axis, are on the same line!
The coordinates of the symmetric point of point a about X axis are A1 (- 6,3), and the coordinates of the symmetric point of point B about y axis are B1 (2, - 5)
Let the linear equation connecting A1B1 be y = KX + B
The coordinates are substituted into:
3=-6k+b
-5=2k+b
k=-1,b=-3
That is: y = - x-3
The coordinate of the intersection point with X axis is: (- 3,0), that is, point D, then: n = - 3
The coordinates of the intersection point with y axis are: (0, - 3), that is, point C, then: M = - 3