The general term of sequence {an} is an = n & # 178; (COS & # 178; n π / 3-sin & # 178; n π / 3), and the sum of the first n terms is SN (1) Find SN; (2) Let BN = s (3n) / (n · 4N), find the first n terms and TN of the sequence {BN}

The general term of sequence {an} is an = n & # 178; (COS & # 178; n π / 3-sin & # 178; n π / 3), and the sum of the first n terms is SN (1) Find SN; (2) Let BN = s (3n) / (n · 4N), find the first n terms and TN of the sequence {BN}

(1) For n = 3K (K ∈ n *), a (3K-2) + a (3K-1) + a (3K) = - 1 / 2 (3K-2) ^ 2-1 / 2 (3K-1) ^ 2 + (3K) ^ 2 = 9k-5 / 2, so s (3K) is the first k term of {9k-5 / 2} and S (3K) = 9K (K + 1) / 2-5 / 2K = 9 / 2K ^ 2 + 2K