If P and Q are two real roots of the equation x2 + (m-2) x + 1 = 0, then (1 + P2 + MP) (1 + Q2 + MQ)=

Because P and Q are the two real roots of the equation, PQ = 1,
By substituting, we can get p ^ 2 + (m-2) P + 1 = 0, Q ^ 2 + (m-2) Q + 1 = 0,
So p ^ 2 + MP + 1 = 2p, Q ^ 2 + MQ + 1 = 2q,
So, (1 + P ^ 2 + MP) (1 + Q ^ 2 + MQ) = 2p * 2q = 4pq = 4

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