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因為p、q是方程的兩個實根,所以pq=1, 代入可得p^2+(m-2)p+1=0,q^2+(m-2)q+1=0, 囙此p^2+mp+1=2p,q^2+mq+1=2q, 所以,(1+p^2+mp)(1+q^2+mq)=2p*2q=4pq= 4 .
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