In p-abc, PA, Pb and PC form a 60 ° angle, PA = a, Pb = B, PC = C, then the volume of p-abc is equal to

First draw a triangular pyramid
BC side height PD through p
PD side height ah through a
First, find the high ah corresponding to the bottom of PBC
PH=PA*1/2*√3/2=√3/4*a
AH^2=PA^2-PH^2=a^2-3/16a^2=13/16a^2
AH=√13/4a
The area of triangular PBC is 1 / 2sinbpc * Pb * PC = √ 3 / 4bc
Volume: ah * s (PBC) * 1 / 3 = 1 / 3 * √ 13 / 4A * √ 3 / 4bc = √ 39 / 48abc

In p-abc, PA, Pb and PC form a 60 ° angle, PA = a, Pb = B, PC = C, then the volume of p-abc is equal to

In p-abc, PA, Pb and PC form a 60 ° angle, PA = a, Pb = B, PC = C, then the volume of p-abc is equal to

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