Some abbreviations The abbreviation of the United Nations is: Abbreviation of the people's Republic of China British abbreviation: American abbreviation: The abbreviation of the United Nations Educational, scientific and cultural organization is:

Some abbreviations The abbreviation of the United Nations is: Abbreviation of the people's Republic of China British abbreviation: American abbreviation: The abbreviation of the United Nations Educational, scientific and cultural organization is:


1)UN
2)P.R.C.
3)UK
4) U.S.A. or U.S.A
5)UNESCO



What is the abbreviation of China?
Why did someone write Chi?


China P.R.C CHN
Chile Chi
Besides, Chinese people don't like to use Chi na



The equation of a circle passing through the intersection of the straight line x + 3y-7 = 0 and the circle x ^ 2 + y ^ 2 + 2x-2y-3 = 0, and the sum of the four intercepts of the two axes is - 8


Because the circle passes through the intersection of the line x + 3y-7 = 0 and the circle x ^ 2 + y ^ 2 + 2x-2y-3 = 0
Let the equation of the circle be
x²+y²+2x-2y-3+λ(x+3y-7)=0
x²+y²+(2+λ)x+(3λ-2)y-(7λ+3)=0
Let x = 0, Y & sup2; + (3 λ - 2) y - (7 λ + 3) = 0
y1+y2=-(3λ-2)
Let y = 0 X & sup2; + (2 + λ) x - (7 λ + 3) = 0
x1+x2=-(2+λ)
y1+y2+x1+x2=-(3λ-2)-(2+λ)=-8
∴λ=2
The equation of the circle is
x²+y²+4x+4y-17=0



Integral (1-cosx) DX / (x-sinx)
Integral [(1-cosx) DX] / (x-sinx)
Be specific
Don't do the above question. It's OK to do it
Change to this question
Integral [(x-3) DX] / [(x ^ 2) + 2x + 3)


∫[(1-cosx)dx]/(x-sinx)
=∫d(x-sinx)/(x-sinx)
=ln(x-sinx)+C
The original formula = ∫ (x + 1-4) DX / (X & sup2; + 2x + 3)
=∫(x+1)dx/(x²+2x+3)-∫4dx/(x²+2x+3)
=1/2∫(2x+2)dx/(x²+2x+3)-∫4dx/[(x+1)²+2]
=1/2∫d(x²+2x+3)dx/(x²+2x+3)-2∫dx/[(x+1)²/2+1]
=1/2*ln(x²+2x+3)-2∫dx/[(x/√2+1/√2)²+1]
=1/2*ln(x²+2x+3)-2√2∫d(x/√2+1/√2)/[(x/√2+1/√2)²+1]
=1/2*ln(x²+2x+3)-2√2arctan(x/√2+1/√2)+C



It is known that the image of the first-order function y = 3x-2k intersects the image of the inverse scale function y = k − 3x, and the ordinate of one of the intersections is 6. The coordinates of the intersection of the image of the first-order function with the X and Y axes are obtained


∵ the ordinate of an intersection is 6, ∵ 6 = 3x − 2K6 = k − 3x, and the solution is k = - 5. ∵ the analytic formula of the first-order function is y = 3x + 10, so the intersection of the first-order function with X axis and Y axis is (− 103,0), (0,10), respectively



1/x+7=[x+1/(2x-1)(x+7)]+(1/2x*2-3x+1)


1 / x + 7 = [x + 1 / (2x-1) (x + 7)] + (1 / 2x * 2-3x + 1) 1 / x + 7 = [x + 1 / (2x-1) (x + 7)] + 1 / [(2x-1) (x-1)] 1 / X + 7 = [(x + 1) (x-1) / (2x-1) (x + 7) (x-1)] + [(x + 7) / (2x-1) (x-1) (x + 7)] 1 / x + 7 = [(x + 1) (x-1) + X + 7] / (2x-1) (x + 7) (x-1) because x + 7 is not equal to 0



Simple calculation of 136 times 37 minus 36 times 37


136*37-36*37=37*(136-36)=37*100=3700



If the function f (x) whose domain is r satisfies f (x) + 2F (- x) = 2x + 1, then f (x) = ()
A. -2x+1B. 2x-13C. 2x-1D. -2x+13


∵ f (x) + 2F (- x) = 2x + 1, ①, let x = - x, then f (- x) + 2F (x) = - 2x + 1, ②, ② × 2 - ①, 3f (x) = - 6x + 1, ∵ f (x) = - 2x + 13, so choose: D



There are only positive numbers whose absolute value is equal to itself
|How about X-2 | + 3? Last question.


Wrong. And 0
The supplementary question is right
|x-2|+3
When x ≥ 2
|x-2|+3=x-2+3=x-1
When x



What is the domain of definition of logarithmic function?
It's the general form
It refers to the base number and the true number


If there is no root sign in the true number formula, you only need to find that the true number formula is greater than zero. If there is a root sign, you need to make sure that the formula in the root sign is greater than zero