If the radius of the ball is r, then the volume of the ball is calculated by the formula v = four-thirds r cube. When the volume v = 500 cubic centimeter, what is the radius r?

If the radius of the ball is r, then the volume of the ball is calculated by the formula v = four-thirds r cube. When the volume v = 500 cubic centimeter, what is the radius r?


500 = (4/3)*Pi*r^3
r=5*3^(1/3)*(π^2)^(1/3)/π=4.92



The formula for calculating the volume of a balloon is ∨ = 3 / 4 of Π R. R is the volume of the balloon, which is 8 times of the original volume, and how many times of its radius?
Thank you very much if you know!
Please list the formula (process)


Let V1 = 4 / 3 * Π R1 ^ 3, V0 = 4 / 3 * Π R0 ^ 3, then because V1 = 8v0, so 4 / 3 * Π R1 ^ 3 = 8 * 4 / 3 * Π R0 ^ 3, so R1 ^ 3 = 8 * R0 ^ 3, so R1 ^ 3 - (2 * R0) ^ 3 = 0, so (r1-2r0) (R1 ^ 2 + 2r1r0 + 4r0 ^ 2) = 0, because R1 ^ 2 + 2r0 + 4r0 ^ 2 ≠ 0, so r1-2r0 = 0, so R1 = 2r0



The volume formula of the known ball is v = 4 / 3 π R v = 500cm. The carpenter wants to make one
The volume formula of the known ball is v = 4 / 3 π R & # 178; v = 500cm. If the carpenter wants to make a cube box to put the ball up, how long should the edge length of the box be at least to put the ball down? (π takes 3)


From the title:
The third power of 4 / 3 × 3 × r = 500
R=5
2*5=10cm
A: the edge length must be at least 10 cm to put the ball down



Given that the distance between two points a and B on the number axis is 1, and the distance between point a and origin o is 4, find the sum of the distances between point B and origin o satisfying the condition
Hurry!


When a = 4, B = 3 or 5
When a = - 4, B = - 3 or - 5



There are four numbers: 76550, 76551, 76552, 76554, in which the product of two data can be divided by 12, then all such two numbers have______ There is a possibility


According to the properties of integer division, 12 is divided into the product of two numbers: 12 = 12 × 1 = 6 × 2 = 3 × 4. To find two of the four known numbers so that their product can be divided by 12, there are three cases: (1) find a number that can be divided by 12, and the product of this number and any of the other three numbers can be divided by 12. (2) find a number that can be divided by 6, and another number that can be divided by 2 (3) find out a number that can be divided by 4 and another number that can be divided by 3, then their product can be divided by 12. It is easy to judge that none of the four numbers can be divided by 12, so case (1) does not exist. For case (2), only 76554 can be divided by 6, while 76550, 76552 are even numbers, so 76554 can be selected And 76550, 76554 and 76552. For case (3), only 76552 can be divisible by 4, and 76551 and 76554 can be divisible by 3, so 76552 and 76552, 7655176552 and 76554 can be selected There are three possibilities for counting



(1) (- 12.5) × (- 6 / 7) × (- 4)=
(2) — 3.14×35.2+6.28×(— 23.3)—1.57×36.4=
(3) (- 12) / (- 1 / 12) / (- 100)=
(4) [(+ 1 and 3 / 4) - (- 7 / 8) + (- 7 / 12)] / (- 7 / 8)=


I don't know how you want to ask for the result, so I write it according to my own. (1) you can see that there are both fractions and decimals. The best way is to use an integer, (- 12.5) x (- 4) = 50, and then it's easy to calculate. As a result, 50x (- 6 / 7) = - 356 / 7 (2) -3.14 and -1.57 are two times, extracting the common factor - 1.5



What is seven eighths minus (two thirds minus one sixth)
Simple calculation


3/8



In a certain period of time in a city, the average daily passenger traffic volume of ground bus is 10000 person times, and the average daily passenger traffic volume of rail transit is 2 times of that of ground bus, less than 690000 person times. How many person times is the average daily passenger traffic volume of rail transit?


The average daily passenger volume of rail transit is 2-690000 person times



Calculate the weight of steel, a steel plate 10 meters long, 5.6 meters wide, 0.05 meters thick, steel density 7.85 g, weight!


Volume = length x width x thickness, weight = Volume X density, 10x5.6x0.05x7.85 = 21.98kg



Two fifths of a batch of cement is used and another 30 tons are transported, which makes the cement 20% more than before. How many tons


3 / 5 left, (3x / 5 + 30) = 1.2x
0.6x=30
X = 50 tons
It was 50 tons