Find some numbers with "three digits equal to the cubic sum of its digits" For example, 153 is equal to the square of 1 plus the square of 5 plus the square of 3

Find some numbers with "three digits equal to the cubic sum of its digits" For example, 153 is equal to the square of 1 plus the square of 5 plus the square of 3

371=3³+7³+1³
Nothing else, I'm sure
If 0 also counts:
370=3³+7³+0³

If the cube of polynomial (K-2) x + Square-6 of K (K-2) x is a cubic trinomial of X, find the value of K

Cubic trinomial
Here are three
So each coefficient is not equal to 0
So K (K-2) ≠ 0
So K ≠ 0 and K ≠ 2

If the cube of polynomial (K-2) x + Square-6 of K (K-2) x is a cubic binomial of X, the value of K is obtained

Cubic binomial
Then K-20 and K (K-2) = 0
Then K2 and (k = 0 or K = 2
therefore
k=0

As shown in the figure, a 10 meter long ladder leans against the wall, and the vertical distance between the top of the ladder and the ground is 8 meters. If the top of the ladder slides 1 meter, then the bottom of the ladder slides to the right by D meters, then d satisfies ()
A. d=1B. d＜1C. 1＜d＜1.1D. 1.1＜d＜1.2

As shown in the figure, ab = a ′ B ′ = 10m, ∵ o = 90 ° is obtained by Pythagorean theorem, Bo = 6m, AA ′ = 1, OA ′ = 7, ob ′ = 51, ∵ 51 ≈ 7.14, ∵ 1.1 ＜ 51-6 ＜ 1.2

The resistance values of the two resistors are 4 Ω and 6 Ω respectively. After they are connected in series to a power supply, the ratio of the voltage at both ends of the two resistors is 0

First of all, the current of the series circuit is equal everywhere and the voltage is unequal. Therefore, from the formula u = IR, we can know the voltage of the two resistors. If I set the current as 1, then U1 = 4 * 1 = 4V, U2 = 6 * 1 = 6V, the ratio of measurement voltage is 4:6, which is reduced to 2:3

The algorithm of 63 × 67 = 6 × (6 + 1) × 100 + 3 × 7 = 4200 + 21 = 4221
RT. his algorithm

63×67=6×（6+1）×100+3×7=4200+21=4221
Multiply two two digit numbers, the two digit numbers satisfy the same ten digits, and the two digit numbers complement each other (the sum equals 10)
Then the last two bits of the product are equal to the product of the bits of the two factors
The number before the product is equal to the product of the ten digit number of the factor and the number greater than one
For example: 83 × 87 = 7221
8×9=72,3×7=21
Do you understand?

There are two resistors R1 and R2, R1 = 10 ohm and R2 = 15 ohm. After they are connected in parallel, what is the total resistance of the circuit?

Total resistance R:
1/R=1/R1+1/R2
R = r1r2 / (R1 + R2) = 6 Ω
The total resistance of the circuit is 6 ohm

As shown in the figure, for the pyramid arrangement composed of natural numbers, first observe its rules. What is the sum of all the books in the first ten lines?
one
2 3 4
5 6 7 8 9
10 11 12 13 14 15 16...

There are 2N-1 numbers in the nth line
According to the summation formula of arithmetic sequence (Gauss formula), there are n ^ 2 numbers in the first n rows, so there are 100 numbers in the first 10 rows
So the sum of all the numbers in the first 10 lines is:
∑=1+2+3+…… +100=（1+100）*100/2=5050

When an electric iron works, the current is 133a, and its resistance is 165 Ω. What is the voltage applied to the electric iron?
Urgent! Please ~ to calculate the process~

Voltage: u = IR = 1.33a x 165 Ω = 219.45v

Simplify the following ratio (1) 1.5:44 (2) 4 / 5:2 / 3 (3) 17:68 (4) 1:0.85 (5) 3 / 10:9 / 25 (6) 8 / 15:15
The first question is 1.5:45, and the last one is wrong, which is 15:8:15

3:88 6:5 1:4 20:17 5:6 8:225