The room department of a hotel has 60 rooms for tourists to live in. When the price of each room is 200 yuan per day, the room can be full. When the price of each room is increased by 10 yuan per day, there will be a room free. For a room with tourists, the hotel needs to pay 30 yuan per day for each room; for a room without tourists, the hotel needs to pay 30 yuan per day for each room If the hotel wants to make a profit of 13400 yuan and ensure a high occupancy rate, how much should the daily price of each room be increased?

The room department of a hotel has 60 rooms for tourists to live in. When the price of each room is 200 yuan per day, the room can be full. When the price of each room is increased by 10 yuan per day, there will be a room free. For a room with tourists, the hotel needs to pay 30 yuan per day for each room; for a room without tourists, the hotel needs to pay 30 yuan per day for each room If the hotel wants to make a profit of 13400 yuan and ensure a high occupancy rate, how much should the daily price of each room be increased?

Suppose that the daily price of each room should be increased by X Yuan, according to the meaning of the question: (200 + x) (60-x10) - (60-x10) × 30-x10 × 10 = 13400, sorted out: x2-420x + 32000 = 0, ∵ = (- 420) 2-4 × 32000 × 1 = 176400-128000 = 48400 ＞ 0, ∵ X1 = 320, X2 = 100. ∵ hotels also need to ensure a higher occupancy rate, ∵ x = 100 The daily price of each room should be increased by 100 yuan

There are 60 rooms in the housekeeping Department of a hotel

When the price is 700 yuan, 10 rooms are occupied by tourists, the income is 7000 yuan, the expenses are reduced by 200 yuan, and the daily profit is 6800 yuan > 6400 yuan

The room department of a hotel has 60 rooms for tourists to live in. When the price of each room is 200 yuan per day, the room can be full. When the price of each room is increased by 10 yuan per day, there will be a room free, The hotel needs to pay 20 yuan for each room every day. Suppose the daily price of each room is increased by yuan. Find (1) the functional relationship between the daily occupancy (rooms) and (yuan). (2) when the daily price of each room is how much yuan, the daily profit of the Room Department of the hotel reaches 15210 yuan?

(1) When the profit is 15210 yuan, y = 15210 yuan
15210=60-X/10
x=210
Price = 210 + 200 = 410 yuan

The volume of a cone is 10.048 cubic meters, and its bottom area is 12.56 square meters. How high is the cone?

Volume of cone v = 1 / 3SH
10.048=1/3*12.56*H
H=2.4

Three sets a = {(x, y) | y = x ^ 2 + 4ax-4a + 3, y = 0}, set B = {(x, y) | y = x ^ 2 + (A-1) x + A ^ 2, y = 0},
At least one set in the set C = {(x, y) | y = x ^ 2 + 2ax-2a, y = 0} is nonempty. Find the value range of real number a

If they have no real roots, then
△1=16a^2-4(-4a+3)=4(4a^2+4a-3)=4(2a+3)(2a-1)-3/2

If the bottom of a triangle is 8 decimeters and the height is 0.2 meters, how many square decimeters is the area of the triangle

9

All prime numbers greater than 2 must be odd______ ．

According to the meaning of prime number and odd number, all prime numbers greater than 2 must be odd

The trapezoid is divided into two triangles. The upper bottom of the trapezoid is 8 cm and the lower bottom is 14 cm. The difference between the triangles is 32.4 square cm. What is the area of the trapezoid?
The trapezoid is divided into two triangles A and B. It is known that the upper bottom of the trapezoid is 8 cm and the lower bottom is 14 cm. If the difference between the two triangles is 32.4 square cm, what is the area of the trapezoid?

Let the height of trapezoid be good h cm
Because the difference between the two triangles is 32.4 square centimeters
So 1 / 2 * (14-8) H = 32.4
The solution is h = 10.8 (CM)
So the trapezoid area is 1 / 2 * (14 + 8) * 10.8 = 118.8 (square centimeter)

A is the point on the circle O with the diameter of BC, passing through point B as the tangent of circle O, intersecting with the extension line of Ca at point D, e is the midpoint of BD, extending AE
If sin ∠ f = 3 / 5, calculate the value of sin ∠ D

Connect AB, OA, DB, tangent circle O to point B, BC is diameter ﹥ DB ⊥ FC to B ﹥ FBE = ﹥ DBC = 90 ° and ﹥ BAC is the circumference angle of diameter BC ﹥ BAC = 90 °﹥ DAB = 180 ° - 90 ° = 90 ° ﹥ DAB is a right triangle. In RT ﹥ DAB, e is the midpoint of hypotenuse BD ﹥ AE = be = BD / 2 ﹥ Abe is the two base angles of isosceles triangular shape ﹥ EAB = ﹥ DBA and ﹥ DBA is the tangent angle of circle O tangent dB and chord ab, So, in the isosceles △ AOC, in the isosceles △ AOC, then, in the isosceles △ AOC, then, in the isosceles △ AOC, in the isosceles △ AOC, in the isosceles △ AOC, in the isosceles △ AOC, in the isosceles △ AOC, in the isosceles △ AOC, in the isosceles △ AOC, OAC is the circular o radius, there are OA = OC = OC. So, in the isosceles, in the isosceles △ AOC, in the isosceles △ AOC, in the isosceles △ AOC, in the isosceles △ AOC, in the isosceles △ AOC, in the isosceles △ AOC, in the R △ AFO, in the R △ AFO, in the △ AFO, in the {SiO = 90, in the @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ in △ FBE, ∠ FBE = 90 ° sin ∠ f = be / EF = 3 / 5 Then, from Pythagorean theorem: EF ^ = be ^ + BF ^, and BF = 2 can be obtained from the combination of ① and ②: be = 3 / 2  BD = 2be = 3. In RT △ DBC: ∠ DBC = 90 ° from Pythagorean theorem: CD ^ = BD ^ + BC ^ can be obtained by substituting BD = 3, BC = 6, and CD = 3 √ 5. Then, sin ∠ d = BC / CD = 6 / (3 √ 5) = 2 √ 5 / 5

As shown in the figure, OA is perpendicular to ob, OC is ray, OM bisects ∠ AOC, on bisects ∠ BOC. 1. If ∠ BOC = 30 °, calculate the degree of ∠ mon
Now there are points

Because OA is perpendicular to ob, so ∠ AOB = 90 °, because om bisects ∠ AOC, so ∠ AOM = (90 ° + 30 °) △ 2 = 60 °, because on bisects ∠ BOC, so ∠ NOC = 30 °△ 2 = 15 °, because ∠ AOC - ∠ BOC - ∠ NOC = ∠ mon = 90 ° + 30 ° - 60 ° - 15 ° = 45 °