Given that the module of vector AB is 1, the root sign is 2, and ab is parallel, find the point of vector a multiplied by vector B

Given that the module of vector AB is 1, the root sign is 2, and ab is parallel, find the point of vector a multiplied by vector B

|A | = 1, | B | = √ 2, because A.B is parallel, the angle of vector A.B is 0 |. A.B = ｜ a ｜. B ｜ cos0 # 180; = 1 ×√ 2 × 1 = √ 2

In tetrahedral p-abc, PC is perpendicular to plane ABC, ab = BC = CA = PC, and the value of dihedral angle b-ap-c is obtained

Because PC is perpendicular to the bottom surface, ACP is perpendicular to ABC. So the vertical line BD of AC through B is the vertical line of ACP, and then the vertical line De of AP through D is connected to be. Then the angle bed is the plane angle of dihedral angle. Since the four line segments are equal, it can be set that they are all equal to a, then BD is equal to the root of two thirds a

Given the vector a = (√ 3sinx, M + cosx), B = (cosx, - M + cosx) and f (x) = a * B,
Find the analytic expression of 1 function f (x)
2 when x ∈ [- π / 6, π / 3], the minimum value of F (x) is - 4. Find the maximum value of F (x) and the corresponding value of X

(1) F (x) = cos (2x-60 degrees) + 0.5-M * m
(2)-2.5

In the right triangle ABC, the angle c equals 90 degrees, AB equals 8cm, Sina equals 3 / 4, then BC equals 0

bc=absina=8*3/4=6

Find the maximum and minimum values of the function f (x) = (2x ^ 2 + 5x + 11) / (x ^ 2 + X + 4), X ∈ [0,2] [please help! Very urgent

F (x) = (2x ^ 2 + 5x + 11) / (x ^ 2 + X + 4) = (2x ^ 2 + 2x + 8 + 3x + 3) / (x ^ 2 + X + 4) = 2 + 3 (x + 1) / [(x + 1 / 2) ^ 2 + 15 / 4] x ∈ [0,2], it is obvious that f (x) is always greater than 2, and 3x + 3, x ^ 2 + X + 4 are increasing functions. Let 3x + 3 = x ^ 2 + X + 4, the solution is x = 1 (two same roots)

It is known that the inscribed circle and hypotenuse BC of RT △ ABC are tangent to point D and right angle AB, and AC is tangent to point E, f respectively, then ∠ EDF =?

90 degrees, aefd is square

Let u = R, a = {x | x ^ 2-x-6 ＜ 0}, B = {x | x-4 | 2}, find a intersection B, a union B, Cu (a intersection b), Cu (a union b)

A=｛x|-2

In the isosceles triangle ABC, ab = AC, be is the bisector of angle ABC, BC = AE + EB

∵ AE = EB ∵ Abe is isosceles triangle ∵ a = ∵ Abe ∵ be is bisector of ∵ ABC ∵ Abe = ∵ CBE = 1 / 2 ∵ ABC ∵ a = 1 / 2 ∵ ABC ∵ ABC = 2 ∵ a ∵ AB = AC ∵ ABC is isosceles triangle ∵ ABC = ∵ C = 2