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Only know kilowatt, how to convert to kilovolt ampere?
KVA is the apparent power, including active power and reactive power
KW is active power
Kilowatt (kw) = kilovolt ampere (kVA) times power factor
Factorization-3ab + 2a-4 + 6B
a(2-3b)-2(2-3b)=(a-2)(2-3b)
Online and so on -- a junior high school physics problem (electric energy, electric power)
The greater the resistance of the electric wire, the more heat it produces, while the smaller the resistance of the electric cooker, the more heat it produces
Why is it not the same under the same voltage of 220 V?
There's something wrong with your saying. The heat generated is determined by current, voltage, resistance and time. How can we say that the greater the resistance is, the more heat will be generated? Who told you that the greater the resistance of electric furnace wire is, the more heat will be generated? For electric furnaces with different power, the higher the power is, the lower the absolute resistance is
(8x + 6y) - (4x + 5Y) = 840-460, how to solve this equation?
（8X+6Y）-(4X+5Y)=840-460
4X+5Y=460.(1)
8X+6Y=840.(2)
(1) * 2 - (2), get
4Y=80
Y=20
Substituting (1),
4X+5*20=460
4X+100=460
4X=360
X=90
Electric power is the physical quantity of current (), and the physical meaning of "20" is ()
Mathematical answer group for you to answer, I hope to help you
Electric power is a physical quantity that represents current (work done per unit time)
The physical meaning of "20" is (the value of work done by the current per unit time is 20)
How to calculate the spring stiffness coefficient
Elastic force divided by the degree of lengthening or shortening of the spring = spring stiffness coefficient
For resistance, capacitance, inductance, diode, triode, the unit conversion. They are represented by what letter. And how to test their quality ah
About what the letters on the circuit board represent, I use the multimeter of dt9205, how to test their quality through the multimeter, I don't know what the numbers on the multimeter mean
The unit of resistance is Ω (Ohm), the unit of capacitance is f (farad), and the unit of inductance is h (Henry). In addition, there are m Ω, K Ω, m Ω (resistance), μ F, PF (capacitance), MH (inductance) and other units after the carry system unit is added. There is no unit for diodes and triodes. The first step to measure with a multimeter is to see which gear to use, and then the reading
Two pieces of wood with mass ma and MB are fixed at both ends of the light spring with stiffness coefficient K. they are vertically placed on the horizontal table top. A vertical downward force is applied to a to make a stand still, and then the force is suddenly removed. How long does the spring need to extend to make B leave the table top?
As shown in Fig. 1, 2, 3 and 4, the spring is in the original length state, the static state after the spring is connected with a, the static state before the pressure f is removed, and the state when a rises to the highest point after the pressure f is removed. After the pressure f is removed, a makes a simple harmonic motion, and the state a is in the equilibrium position Length, the elastic force is equal to the gravity of B, kx2 = MBG; from the symmetry of simple harmonic motion, the distance from state a to the equilibrium position is equal to the amplitude, so to make B leave the table, the spring needs to extend at least x = X1 + x2 = (MA + MB) GK; a: to make B leave the table, the spring needs to extend at least (MA + MB) GK
It is known that: in △ ABC, ∠ a = 60 ° AB + AC = 12, let AB = x and the area of △ ABC be s, then the functional relationship between S and X is obtained
I have the answer: B is triple root three, a is minus quarter root three
As BD ⊥ AC in D
∵∠ABD=90°-∠A=30°.
In a right triangle, the right side opposite by an internal angle of 30 degrees is half of the hypotenuse
From Pythagorean theorem: BD = √ (AB & # 178; - Ad & # 178;) = √ [x & # 178; - (1 / 4) x & # 178;] = (√ 3 / 2) X
So s = (1 / 2) ac * BD = (1 / 2) * (12-x) * (√ 3 / 2) x = (- √ 3 / 4) x & # 178; + 3 √ 3x
The mass of a spring scale pan is 1.5kg, the mass of an object P placed in the pan is 10.5kg, and the stiffness coefficient is 800kg. The system is in balance
The mass of a spring scale pan is 1.5kg, the mass of an object P placed in the pan is 10.5kg, and the stiffness coefficient is 800kg. The system is in balance. Now, a vertical upward force F is applied to p to make p do uniform acceleration motion from static state. It is known that f is a variable force in the first 0.2S, and F is a constant force after 0.2S. The maximum and minimum value of F is obtained
Note a - left front wheel
B - right front wheel
C - left rear wheel
D -- right rear wheel
Then the pressure on each wheel is Na (car) = Nb (car) = NC (car) = Nd (car) = 1 / 4 × 800 × 10 = 2000N / kg
Na (person) + Nb (person) + NC (person) + Nd (person) = 75 × 10 = 750N
[Na (person) + NC (person)] × 1 / 5 = [Nb (person) + Nd (person)] × 4 / 5
[Na (person) + Nb (person)] × 1 / 3 = [NC (person) + Nd (person)] × 2 / 3
[Na (person) + Nb (person)] × 1 / 2-750 × (1 / 2-1 / 3) = [NC (person) + Nd (person)] × 1 / 2
The solution is: Na (human) = 350n; Nb (human) = 150; NC (human) = 250N; Nd (human) = 0n
Na=2350N； Nb=2150N； Nc=2250N； Nd=2000N
The rolling resistance of each wheel is:
Fa=117.5N； Fb=107.5N； Fc=112.5N； Fd=100N
Let the center of mass of the vehicle and the driver be 1 / y to the left of the vehicle
Then 800 × (1 / 2-1 / y) = 75 × (1 / Y-1 / 5)
The solution is 1 / y = 83 / 175
Moment of left wheel resistance relative to mass center = mleft = (FA + FC) × 83 / 175 = 19090 / 175
Moment of right wheel resistance relative to mass center = m right = (FB + FD) (1-83 / 175) = 19090 / 175
M left = m right
The car will not deflect
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