Seeking indefinite integral ∫ 1 / (3x-1) ^ 2 * DX

Seeking indefinite integral ∫ 1 / (3x-1) ^ 2 * DX

A:
simple form
=1/3∫1/(3x-1)^2*d(3x-1)
=1/3*(-1/(3x-1))+C
=-1/(3(3x-1))+C

What is the single digit of 9 × 19 × 29 × 39 ·····× 2009?

Every 100 digits has 10 digits, and every 1000 digits with 9 digits contains 10 100s
So there are 100 9's in 1000
The total is 2 * 100 + 1 = 201
9*9=81 1*9=9 9*9=81
So every two nines multiplied by one digit is one
So 201 contains 100 pairs, plus a separate 2009
So it must be 9

2x-5y-4 = 0, find the value of 4 ^ x △ 32 ^ y
process

X = 1 / 2 (4 + 5Y) original formula = 4 ^ 1 / 2 (4 + 5Y) △ 32 ^ y = 2 ^ (4 + 5Y) △ 32 ^ y = 16 * 2 ^ 5Y △ 32 ^ y = 16

Negative 3 [1 minus 1 / 6] is equal to?

Original formula = - 3 + 1 / 2 x

Given that the domain of definition of the function y = √ KX ^ 2 + 4kx + 3 is r, find the value range of K
Another question is that the inequality x ^ 2 + MX + 1 > 2x + m satisfies | X|

Because the definition field of function y = √ KX ^ 2 + 4kx + 3 is r, so KX ^ 2 + 4kx + 3 > = 0 holds for all X. when k = 0, the inequality becomes 3 > = 0, so k = 0 satisfies the condition. When k is not equal to 0, the image of function y = KX ^ 2 + 4kx + 3 is a parabola, because the inequality y = KX ^ 2 + 4kx + 3 > = 0 holds, indicating that the parabola

What is the product of 15.5 divided by {not divided by} 6 and 1 / 5 times the reciprocal of 0.25?
It's all wrong

6 and 1 / 5 divided by 1 5.5 times 0.25 is 31 / 100

How to look at the degree and number of terms of a polynomial and the number of times and expressions of constant terms?

Polynomial degree: the degree of the letter index and the largest monomial; number of terms: the number of monomials (including the constant term without letters); constant term: the term without letters. In short, the number of times of the letter index and the largest monomial is "several times", and several monomials are "several times"

How to write the mathematical expression of sum difference product formula?

Sum difference product of sine and cosine sin α + sin β = 2Sin [(α + β) / 2] · cos [(α - β) / 2] sin α - sin β = 2cos [(α + β) / 2] · sin [(α - β) / 2] cos α + cos β = 2cos [(α + β) / 2] · cos [(α - β) / 2] cos α - cos β = - 2Sin [(α + β) / 2] · sin [(α - β) / 2]

(radical Mn) - (M / N of radical) / (M / N of radical)

（√MN-√M/N）/√M/N
＝√MN/√M/N-√M/N/√M/N
＝（√MN*√N）/√M-1
＝N√M/√M-1
＝N-1

One eighth divided by (how much minus one fourth) equals three quarters

One eighth divided by (5 / 12 minus one fourth) equals three quarters