The runway of an aircraft carrier is 200m long, and the total weight of the aircraft is 16t. The minimum take-off speed of the aircraft is 50M / s, If the acceleration of the aircraft is 4m / S-2, what is the minimum speed required for the aircraft carrier to take off normally?

The runway of an aircraft carrier is 200m long, and the total weight of the aircraft is 16t. The minimum take-off speed of the aircraft is 50M / s, If the acceleration of the aircraft is 4m / S-2, what is the minimum speed required for the aircraft carrier to take off normally?

The speed that an aircraft can achieve by accelerating itself is V1
V1²=2aS=2×4×200=1600,V1=40m/s
So the minimum speed of the aircraft carrier is V2 = 50-40 = 10m / s
Here, taking the aircraft carrier as the reference frame, the aircraft starts to be stationary relative to the aircraft carrier, and the acceleration distance is 200 meters. If the ground is taken as the reference frame, the aircraft and the aircraft carrier are moving, and the acceleration distance is unknown

How much is a number equal to 20% of 205 and 115? 2. How much is the sum of a number and 18 equal to 45% of 60?

1、205×20％=41 41+115=156
2、60×45％=27 27-18=9
I want to score more points by myself!

How to make a bridge with a piece of newspaper and a small amount of adhesive tape,
Can not use other materials, to interval for 30 cm, load for 4 weights, 30 grams each

Have you ever seen the paper fan folded by a child like that

2(2x+3)=5x-7

2(2x+3)=5x-7
4x+6=5x-7
5x-4x=6+7
x=13

The distance between port a and port B is 120 km. Ship AB runs from port AB for 6 hours and meets each other. A goes with the water and B goes against the water. When meeting, ship a travels 49 km more than ship B and the current is 1.5 km
Finding the still water velocity of AB ship

Let a's hydrostatic velocity be x km / h and B's hydrostatic velocity be y km / h
6（x+1.5）-6（y-1.5)=49
6（x+1.5）+6（y-1.5)=120
The solution is: x = 151 / 12, y = 89 / 12

AB (a square B) - b square (ab-2a) - 3AB square

AB (a square B) - b square (ab-2a) - 3AB square
=a^3b^2-ab^3+2ab^2-3ab^2
=a^3b^2-ab^3-ab^2

Simple calculation of 995 times 997

999 and 995 out of 997 times 997
=(1000-2/997)*997
=997000-2
=996998

A total of 1300 kg of apples and pears were delivered to the fruit shop. Two fifths of the apples were sold. After 20 kg of pears were sold, the weight of the remaining pears and apples was exactly the same as the original
How many kilos of apples and pears each?

Apple (1300-20) / (1 + 3 / 5)
=1280÷8/5
=800 kg
Pear 1300-800 = 500kg

Know that a + B is less than or equal to 1, greater than or equal to 5, A-B is greater than or equal to - 1, less than or equal to 3, find the value range of 3a-2b

Let: 3a-2b = x (a + b) + y (a-b) get: x + y = 3, X-Y = - 2 have: 3 (a + b) less than or equal to 3, greater than or equal to 15 - 2 (a-b) greater than or equal to - 6, less than or equal to 2, because the title is wrong: the above formula can not be accumulated; the estimate should be: greater than or equal to 1, less than or equal to 5, if so, according to the above

If Z1 = 1-2i, Z2 = I, then | Z1 + Z2 | =?
If it's 2 or 0, is it because I = 1 or - 1?

2 or 0