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There are 56 students in class 5 (4) of the school. The number of girls is three fifths of that of boys. How many boys are there?
Set X for boys and 3 / 5x for girls
x+3/5x=56
8/5X=56
X=35
A: there are 35 boys
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There are 56 students in class 1 of grade 6. They take part in extracurricular activities at one time. Eight of them take part in football group. The rest take part in table tennis group and basketball group according to the ratio of 5:7
56-8 = 48
5+7=12
Table tennis group: 48 × 5 / 12 = 20
Basketball group: 48 × 7 / 12 = 28
What are you asking for?
There are 56 students in class 5, grade 6, among which the number of boys is three fourths of that of girls. How many boys and girls are there respectively?
The main formula
Suppose the number of girls is x, then the number of boys is 3 / 4 times of X, and the sum is 7 / 4 times of X. 56 students in the class = 7 / 4 times of X. if x = 32, then 3 / 4 times of X is 24. So there are 32 girls and 24 boys
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Fill in the number 82.357 23.578 35.782 () ()
57.823 78.235 move each decimal point back one place
The sum of two adjacent natural numbers is 37. How many natural numbers are there in these two days? Solve the equation
Let XX + X + 1 = 372x = 37-12x = 36x = 18 be 18 and 19 respectively ~ if you agree with my answer, please click the [adopt as satisfied answer] button in time ~ ~ the mobile phone questioner can click [satisfied] in the upper right corner of the client. ~ your adoption is my driving force ~ ~ ~ if you have any new questions, please ask me for help in addition
What is the third root of 192
Cubic root!
Look down the stairs
192=4^3*3
So the third root of 192 is 4 times the root sign 3
Simple calculation of 169 × 5 △ 13
Solution
169×5÷13
=13×13×5÷13
=13×5
=65
Can (x + 1) (x ^ 2-2x-1) be simplified
Original formula = x (X & # 178; - 2x-1) + 1 * (X & # 178; - 2x-1)
=x³-2x²-x+x²-2x-1
=x³-x²-3x-1
There are 25 calculation questions for binary linear equations,
1,x-y=2 xy=15 (x=5,y=3) 2,x+y=6 x-y=2 (4,2) 3,x+y=11,xy=30 (x=5,y=6,x=6,y=5) 4,x+y=13,xy=42 (x=6,7,y=7,6) 5,x+y=11,x-y=1 (x=6,y=5) 6,x+y=12,xy=35 (x=5,7,y=7,5) 7,x+y=5,xy=6 (x=2,3,y=3,2) 8,x-y=5,xy=36...
The bottom of a cuboid container is a square with a side length of 60 cm. In the container stands a cuboid iron block with a height of 1 m and a side length of 15 cm. At this time, the water depth in the container is 0.5 m. now lift the iron block up gently for 24 cm. How long is the water soaked part of the iron block above the water surface?
15 × 15 × 24 (60 × 60-15 × 15) = 5400 △ 3375 = 1.6 (CM) 24 + 1.6 = 25.6 (CM) a: the length of the water soaked part on the iron block above the water surface is 25.6 cm
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