Five workers process 735 parts 735 parts were processed by one worker, and 135 parts were processed in two days. It is known that one of the two workers asked for leave for two days. If no one asked for leave in the next few days, how many days would it take to complete the task? The answer is 135 ± (5 × 2-1 × 1) × 5 = 75 (735-135) ± 75 = 8 days Why use 5x2 to explain each step in detail

Five workers process 735 parts 735 parts were processed by one worker, and 135 parts were processed in two days. It is known that one of the two workers asked for leave for two days. If no one asked for leave in the next few days, how many days would it take to complete the task? The answer is 135 ± (5 × 2-1 × 1) × 5 = 75 (735-135) ± 75 = 8 days Why use 5x2 to explain each step in detail


The first step is to calculate the number of parts processed by five people in one day by the formula 135 △ (5 × 2-1 × 1) × 5 = 75. If five people process 135 parts in two days and one person calculates one "work" in one day, five people in two days are 5 × 2 and ten "work". If one person takes one day off, minus one work, that is (5 × 2-1 × 1) =



Five workers processed 735 parts and 135 parts in two days. It is known that one of the two workers asked for leave for one day. According to the work efficiency, if no one asked for leave in the next few days, how many days will it take to complete the task?


The number of parts processed by each person per day: 135 (2 × 5-1 × 1) = 15, the number of parts processed by 5 persons per day: 15 × 5 = 75, the remaining workload: 735-135 = 600, and the number of days needed is 600 / 75 = 8. A: it will take 8 days to complete the task



The price of 500 grams of tea is 98 yuan, 0.05 kg for each 500 grams. Uncle Li wants to buy 2.2 kg of tea, how much should he pay? I have finished the question


2.2kg divided by 0.55kg equals 4.4 times 98 yuan equals 392 yuan a: 392 yuan should be paid



How to judge quadratic function image?


Grasp the key
For y = ax & sup2; + BX + C (a is not equal to 0)
A is to determine the opening direction, a > 0, opening upward, A0, two intersections, △ = 0, one intersection, △ 1



Make a formula with 5's, let the result be equal to 0, if (addition, subtraction, multiplication and division) can only be used once


(5-5)*(5/5+5)



It is known that the equation x-ax + (a + 3) = 0 has two equal real roots, a =


X-ax + (a + 3) = 0 has two equal real roots, which indicates that the discriminant △ = 0
△=a²-4(a+3)=0 a²-4a-12=0 (a+2)(a-6)=0
A = - 2 or a = 6



What kind of operation symbol and bracket are added in the middle of 5 0.2 to make both sides of the equal sign equal?
0.2 0.2 0.2 0.2 0.2 =3
0.2 0.2 0.2 0.2 0.2 =5


0.2 / 0.2 +( 0.2 + 0.2 )/ 0.2 =3
(0.2 / 0.2) / 0.2 + 0.2 - 0.2 =5



If the function f (x) = tanwx (W > 0), the two adjacent tangent lines y = 1, the length of the obtained line segment is π / 4, and f (π / 12) is equal to


If f (x) = tanwx (W > 0), the two adjacent tangent lines y = 1, the length of the line segment is π / 4,
Then the period of F (x) t = π / w = π / 4
∴w=4
f(x)=tan4x
f(π/12)=tanπ/3=√3



Mathematics exercise book grade 5 Volume 1 page 76 answers


1000÷10=100
100×6.05=650



(a) it is known that the length of the minor axis of the ellipse is 2, the center of the ellipse coincides with the vertex of the parabola y2 = 4x, and a focal point of the ellipse is exactly the focal point of the parabola, so as to find the length of the elliptic equation and its major axis. (b) it is known that a pair of internal angles of the diamond are 60 ° and the side length is 4, and the rectangular coordinate system is established with the straight line where the diagonal of the diamond is located as the coordinate axis Vertex as the focus, and through the other two vertices of the diamond ellipse, elliptic equation


(a) let the elliptic equation be x2a2 + y2b2 = 1 ∵ 2B = 2, ∵ B = 1. From the parabolic equation y2 = 4x, we can know its focus and (1,0), so the point (1,0) is also a focus of the ellipse, so C = 1, so A2 = B2 + C2 = 2, a = 2, so the elliptic equation is X22 + y2 = 1, and the length of the major axis is 22