(- 0.2) cube x (- 50) + (- 1 and 2 / 5) cube x (- 5 / 7) cube

(- 0.2) cube x (- 50) + (- 1 and 2 / 5) cube x (- 5 / 7) cube

(- 0.2) cube x (- 50) + (- 1 and 2 / 5) cube x (- 5 / 7) cube
=-0.08x (- 50) + (7 / 5 × 5 / 7) cubic
=-4+1
=-3

Solve the equation: the cube of 3x plus 81 / 125 equals 0

The cube of 3x plus 81 out of 125 equals 0
3 * (cube of X + 27 / 125) = 0
Cube of X + cube of (3 / 5) = 0
(x + 3 / 5) (the square of X - 3 / 5x + 9 / 25) = 0
x3/5=0
x=-3/5

The third power of (X-5) = - 64

The third power of (X-5) = - 64
The third power of (X-5) = the third power of - 4
x-5=-4
x=1

It is known that the inverse scale function y = k2x and the first-order function y = 2x-1, in which the image of the first-order function passes through two points (a, b) and (a + K, B + K + 2) (1) to find the analytic expression of the inverse scale function; (2) it is known that a is in the first quadrant, which is the intersection of two functions, to find the coordinates of point a

(1) ∵ the image of a function y = 2x-1 passes through two points (a, b) and (a + K, B + K + 2) ∵ 2A − 1 = B & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; ① 2 (a + k) − 1 = B + K + 2 & nbsp; & nbsp; ② By substituting B = 2a-1 into 2 (a + k) - 1 = 2a-1 + K + 2 of 2, the solution is: k = 2, so the analytic expression of inverse proportion function y = k2x is: y = 1x; (2) simultaneous inverse proportion function and linear function are: y = 1xy = 2x − 1, that is, 1x = 2x-1, the solution is: x = - 12 or x = 1, ∵ a in the first quadrant, ∵ x = 1, ∵ y = 1, ∵ a point coordinates are (1,1)

Why is the minimum value of A2 + B2 8 when ab ≤ 8?
Such as the title

(a-b)^2≥0,
a2+b2-2ab≥0,
a2+b2≥2ab,
And 2Ab ≤ 16,
∴a2+b2≥16

As shown in the figure, ad is the height of △ ABC, make ∠ DCE = ∠ ACD, intersect the extension line of ad at point E, and point F is the symmetrical point of point c about the straight line AE, connecting AF. (1) prove: CE = AF; (2) take a point n on the line AB, make ∠ ENA = 12 ∠ ace, and en intersect BC at point m, connecting am. Please judge the quantitative relationship between ∠ B and ∠ MAF, and explain the reason

(1) It is proved that: ∵ ad is the height of △ ABC, ∵ ADC = ∵ EDC = 90 °, ∵ DCE = ∵ ACD, ∵ ace is isosceles triangle, ∵ AC = CE, and ∵ point F is the symmetry point of point c about AE, ∵ AF = AC, ∵ AF = CE; (2) ∵ B = ∵ MAF, ∴∠1=∠3，∵AC=AF，∴∠4=∠ACD，∵∠ENA=12∠ACE，∠DCE=∠ACD=12∠ACE，∴∠ACD=∠ENA，∴∠4=∠ENA，∵∠4=∠1+∠MAF，∠ENA=∠3+∠B，∴∠B=∠MAF．

The square of X is 17. What is x?

Root 17

The area of a trapezoid is 240 square centimeters, the height is 10 cm, the top is 9 cm, and the bottom is several cm

(9 + x) * 10 = 2 * 240, x = 39cm

If the triangle ABC is an axisymmetric figure, then its axis of symmetry is?

The line on which the bisector of the vertex is located

How to solve the equation with the square of X + 10x + 16 = 0

∵ x + 10x + 16 = 0 ∵ x + 10x + 16 + 9 = 9 ∵ (x + 5) = 9, then (x + 5) ′ = 3, (x + 5) ″ = - 3 ∵ x ′ = - 2, X ″ = - 8