If the algebraic formula x2-2x-3 is changed into the form of (x-m) 2 + K, where m and K are constants, then M + K=______ ．

If the algebraic formula x2-2x-3 is changed into the form of (x-m) 2 + K, where m and K are constants, then M + K=______ ．

∵ x2-2x-3 = x2-2x + 1-4 = (x-1) 2-4, ∵ M = 1, k = - 4, ∵ m + k = - 3

If the algebraic formula x2-2x-3 is changed into the form of (x-m) 2 + K, where m and K are constants, then M + K=______ ．

∵ x2-2x-3 = x2-2x + 1-4 = (x-1) 2-4, ∵ M = 1, k = - 4, ∵ m + k = - 3

If the algebraic formula X-2 x-3 is transformed into the form of (x-m) square-k, where m and K are constants, then M + K=

x²-2x-3
=x²-2x+1-4
=(x-1)²-4
=(x-m)²-k
∴m=1,k=4
∴m+k=5

The square of (10-11) times the square of (11-12) times What's the square of 99-100

Every bracket is - 1, and the square is followed by 1. Is this 89 1 multiplied by 1

It is known that the sequence an is an equal ratio sequence, the common ratio q = - 1 / 3, and the value of LIM (a1 + a3 +. A2n-1 / A2 + A4 +. + A2N)

-3

There are two polynomials: 1. There are only letters in the polynomials. 2. The absolute values of the coefficients in each polynomial are 1. 3. The sum of the two polynomials is one
The difference between these two polynomials is a quadratic monomial
What are the two polynomials
2. If the quartic and quadratic monomials in condition 3 are changed to quartic and quadratic polynomials respectively, please write two more polynomials that meet the conditions

(1) Note: (a) two polynomials must be quartic polynomials with opposite coefficients; (b) there is no cubic term in two polynomials, otherwise "sum" or "difference" will be cubic; (c) there is no quadratic term and constant term in two polynomials, otherwise "sum" or "difference" will be multiple

A barrel of oil weighs 20.5 kg. After half use, the barrel weighs 11 kg. How many kg of oil is there in the barrel?

If there is oil x kg, the barrel weight is (20.5-x) kg
According to the weight of the front and rear barrels
0.5x+（20.5-x）=11
x=19
A: there was 19 kg of oil

a> When x is not equal to 0, f (x) = | x | ^ A * sin (1 / x). When x = 0, f (x) = 0. When we find out the value of a, f (x) is differentiable

f'(0)=lim[f(x)-f(0)]/(x-0)=lim|x|^a*sin(1/x)/x=lim|x|^（a-1）*sin(1/x)
existence
therefore
a>1
There is
f'(0)=0
[|x ^ (A-1) is infinitesimal, sin (1 / x) is bounded function]

How to solve the equation (X-7) / (x-24) = 7?
fast

Unfold
x-7=7(x-24)
x-7=7x-168
6x=161
x=161/6

How many hours does it take to pump 90 cubic meters of water at this speed?

It takes 3017 hours to pump 90 cubic meters of water