Square of (x-1) = 16 and cube of 8 (x + 1) = 16 The second is equal to 27

Square of (x-1) = 16 and cube of 8 (x + 1) = 16 The second is equal to 27

Square of (x-1) = 16
x-1=±4
x=-3,x=5
Cube of 8 (x + 1) = 27
Cube of (x + 1) = 27 / 8
x+1=3/2
x=1/2

(x-a-b) (a-b-x + 8) = 7, find the square of (x-a-b) + (a + b-X + 8)

(x-a-b) (a + b-X + 8) = 7 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; a new order x-a-b = TT (8-t) = 78t-t & # 178; = 7T & # 178; - 8t + 7 = 0 (t-1) (T-7) = 0t = 1 or T = 7T = 1 (x-a-b) square + (a + b-X + 8) square = 1 + (8-1) square = 1 + 49 = 50t = 7 (x-a-b) square + (

Xiaohua read a book, read two-thirds of the whole book in eight days, and then read 60 pages in four days, just finished reading. How many pages of this book?
Thanks for the answer, but I want the process. I just forgot to write it

180 pages
Eight days reading two thirds, that four days is read one third, one third is 60 pages, a total of 180 pages

If a is the first quadrant angle, then the value range of 2a is; if 2a is the second quadrant angle, then a is the quadrant angle

（1）∵2kπ

How many milliseconds equals one second?

One millisecond is equal to one thousandth of a second (10-3 seconds). 0.000 000 001 millisecond = 1 picosecond. 0.000 001 millisecond = 1 nanosecond. 0.001 millisecond = 1 microsecond. 1000 millisecond = 1 second

If the equation x ^ 2 / M + y ^ 2 / (m ^ 2-2) = 1 represents ellipse, find the value range of real number M

The equation x ^ 2 / M + y ^ 2 / (m ^ 2-2) = 1 represents an ellipse
Ψ m > 0 and M & # 178; - 2 > 0 and m ≠ M & # 178; - 2
Ψ m > √ 2 and m ≠ 2 and m ≠ - 1
The value range of M is (√ 2,2) U (2, + ∞)

The known function f (x) = 2cos ^ 2 (x + π / 12) + 2sinxcosx-3 needs to be reduced to the form where the minimum positive period can be obtained
Please hurry up, thank you very much, QAQ

F (x) = 2cos & # 178; (x + π / 12) + 2sinxcosx-3 double angle formula 2cos & # 178; (x + π / 12) = 1 + Cos2 (x + π / 12) = 1 + cos (2x + π / 6) + sin2x-3 = cos2x * cos π / 6-sin2x * sin π / 6 + sin2x-2 = cos2x * √ 3 / 2-sin2x * 1 / 2 + sin2x-2 = √ 3 / 2cos2x + 1 / 2sin2x-2 = sin (2

If the intersection of the line x + 2Y + K + 1 = 0 and the line 2x + y + 2K = 0 is in the third quadrant, the value range of K is obtained
be deeply grateful.

Solve the equations {x + 2Y + K + 1 = 0,2x + y + 2K = 0
We obtain {x = 1 / 3-K, y = - 2 / 3
Because the intersection is in the third quadrant
So 1 / 3-K < 0
So k > 1 / 3
If you don't understand, please ask, I wish you a happy study!

In the function y = 3x & # 178; + 2x-1, the value range of automatic variable x is ()

The whole set of real numbers R

If the surface area of a cube is 54 square centimeters, then the area of each side is () square centimeters, its edge length is () centimeters, and its volume is () cubic

If a cube has six faces and the surface area is 54, then the area of each face is 54 / 6 = 9 square centimeters;
If the area of a surface = edge length * edge length, the side length can be deduced to be 3cm (because 3 * 3 = 9cm2);
Volume = 3 * 3 * 3 = 27 CC