The square of x minus the second power of 5} + 8 {the second power of 5-x} plus 16

The square of x minus the second power of 5} + 8 {the second power of 5-x} plus 16

It's x ^ 2-5 ^ 2 + 8 (5-x ^ 2) + 16
Or (x ^ 2-5) ^ 2 + 8 (5-x ^ 2) + 16
If it is factorization, it is (x ^ 2-5) ^ 2 + 8 (5-x ^ 2) + 16 = (x ^ 2-5) ^ 2-8 (x ^ 2-5) + 16 = (x ^ 2-5) ^ 2 + (- 4-4) (x ^ 2-5) + (- 4) * (- 4) = (x ^ 2-5) - 4) ^ 2 = (x ^ 2-9) ^ 2

If x, y and Z satisfy x + y = 5 and Z ^ 4 = XY + Y-9, then x + 2Y + 3Z=______

y=5-x
z^4=x(5-x)+(5-x)-9=-(x-2)^2>=0
x=2
y=3
z=0
x+2y+3z=8

Given that real numbers x, y and Z satisfy x + y = 4 and xy = Z2 + 4, we can find the value of X + 2Y + 3Z

∵ real numbers x, y, Z satisfy x + y = 4 and xy = Z2 + 4, ∵ the quadratic equation with X, y as roots is t2-4t + Z2 + 4 = 0, where △ = 16-4 (z2 + 4) = - 4z2 ≥ 0, so z = 0, substituting x = y = 2, then x + 2Y + 3Z = 6

If the equation AX = 2 about X has no solution, then the value of real number a is

ax=2
If a is 0, there is no solution,
Then the value of real number a is 0

What is the relationship between the sign and absolute value of the sum of two rational numbers and the sign and absolute value of the addend

If two numbers have the same sign, the sign of the sum takes the original sign of the two numbers, and the absolute value of the sum takes the sum of the absolute values of the two numbers
If two numbers have different signs, the sign of sum takes the sign of the number with the larger absolute value, and the absolute value of sum takes the difference between the absolute values of two numbers

Function f (x) = x | x-a | 1. When a = 2, find the monotone interval of function 2. Discuss the number of zeros of function y = f (x), and find the zeros

1. When x > 2, f (x) = x (X-2) = (x-1) ^ 2-1; monotone interval: x > 2, f (x) monotone increasing
When x

If a is less than 0 and B is less than 0, then a + B () 0, the absolute value of a + B is equal to ()

Because
a

Let f (x) be defined on (- ∞, + ∞) and an odd function with period 2. If x ∈ (2,3) is known, f (x) = x & # 178; + X + 1, then if x ∈ [- 2,0], f (x)=
There is a sentence in the solution: Let f (x) be defined on (- ∞, + ∞) and be an odd function, so f (0) = 0,
How did this come out
And: the period is 2, so f (2) = f (0) = 0, and f (- 1) = - f (1) = - [f (1-2)] = - f (- 1), so f (- 1) = 0,
I don't understand the derivation of F (- 1),

Because f (x) is defined on (- ∞, + ∞) and is an odd function
So f (x) = - f (- x)
Let x = 0, then f (0) = - f (0)
So 2F (0) = 0, so f (0) = 0
Because f (x) is an odd function, f (1) = - f (- 1)
And the period of F (x) is 2, so f (1) = f (1-2) = f (- 1)
So f (1) = - f (- 1) = f (- 1)
So 2F (- 1) = 0, so f (- 1) = 0

If the maximum value of the function y = - x ^ 3-2x + 3 in the interval [a, 2] is 15 / 4, then a=

Have you studied derivatives? If so,
Y = - x ^ 3-2x + 3, then
y '=-3x^2-2

If f (x) = AX2 + 2x + B and f (x) is an odd function, then f (2)=

The function f (x) is odd
-f(x)=f(-x)
-(ax²+2x+b)=ax²-2x+b
So a = 0, B = 0
f(x)=2x
f(2)=4