If the function y = x & # 178; + 2x-k has a maximum value of 0 in the interval [- 2,3], then the value of K is

If the function y = x & # 178; + 2x-k has a maximum value of 0 in the interval [- 2,3], then the value of K is


y=x²+2x-k
=(x+1)^2-k-1
Axis of symmetry x = - 1
So the maximum at x = 3 is zero
ymax=15-k=0
k=15



Try to find the maximum K of the function y = - x * x + 2mx + 2 on 0 ≤ x ≤ 2


y=-x²+2mx+2
x=-2m/-2=m
1)m2
f(x)max=f(2)=-2+4m=k



Try to find the maximum value k of the function y = - x ^ 2 + 2mx + 2 on x greater than or equal to 0 and less than or equal to 2


y=-x^2+2mx+2 0≤x≤2
x=m
1)m2
f(x)max=f(2)=-4+4m+2=4m-2



(44 / 3 - 33 / 10) divided by 11 / 5


Original formula = 44 / 3 * 5 / 11 + 33 / 10 * 5 / 11
=20/3+3/2
=40/6+9/6
=49/6



A question about the proof that a ~ empty set is a subset of any set
An empty set is a subset of any set. I have seen the proof of the opposite proof, but I don't think it can prove that an empty set is a subset of any set, because as long as X belongs to an empty set, we can deduce a contradiction, no matter whether x belongs to a set or not. In this way, we can say that an empty set is not a subset of any set with the idea of the inverse method, Then there exists x belonging to an empty set and a, which has no contradiction with the empty set


According to the definition of subset, if an element in a is also an element in B, then a is a subset of B. its inverse negative proposition is that if a is not a subset of B, then an element in a is not an element in B



The solution of equation 5x-3 (m-5) = 0 is the same as that of equation 3 (3x-1) - 2 (6 + 5x) = 0, and the value of M is obtained


5x-3(m-5)=0
5x=3(m-5)
x=3(m-5)/5
3(3x-1)-2(6+5x)=0
9x-3-12-10x=0
x=-15
So 3 (m-5) / 5 = - 15
m-5=-25
m=-20



Just use the number 8 to make up five numbers and fill in the box below to make the formula true______ ﹢______ ﹢______ ﹢______ ﹢______ =1000.


According to the stem analysis can be: 888 + 88 + 8 + 8 + 8 = 1000, so the answer is: 888; 88; 8; 8; 8



(x + 2) parts (x + 1) + (x + 5) parts (x + 4) = (x + 3) parts (x + 2) + (x + 4) parts (x + 3) solve this equation


(x + 2) of (x + 1) + (x + 5) of (x + 4) = (x + 3) of (x + 2) + (x + 4) of (x + 3)
x=-7/2



(sin22°+cos45°sin23°)/(cos22°-sin45°sin23°)=


If we expand sin22 into sin45cos23-cos45sin23 and cos22 into cos45cos23 + sin45sin23, we can get the original formula = tan45 = 1



40 out of 100 of a number is 3 out of 10 less than 25 out of 100 of 2.8


Set this number to X
x 40% - 2.8x25%= -3/10
0.4x - 0.7 = -0.3
0.4x= 0.4
x=1