Find the tangent equation of the curve X squared plus 1 / 3 x at point 2 and 4 / 3 Bonus points! Correct answer and high score. It's urgent now! The problem is that I don't know the result of derivation! Great Xia, help!

Tangent equation of F (x) = x / (x ^ 2 + 1) at point (2,2 / 3)
First, take the derivative of F (x), and substitute 2 into the slope of the tangent, then use the oblique formula of the straight line

Using derivation: the tangent at m on the curve y = x square - 1 / 16 is perpendicular to the straight line 2x + y + 1 = 0. The tangent equation is obtained

The tangent at m on the curve y = x Square-1 / 16
Slope K1 = y '= 2x
x=m
k1=2m
Line 2x + y + 1 = 0
k2=-2
The tangent at m on the curve y = x Square-1 / 16 is perpendicular to the line 2x + y + 1 = 0
So: k1k2 = - 1
k1=1/2
So: 2m = 1 / 2
m=1/4
At this time:
y=m^2-1/16=0
So let the linear equation be:
y=1/2*x＋b
Passing (1 / 4,0) point
Substitute:
0=1/8+b
b=-1/8
So the tangent equation is:
y=x/2 -1/8

3ax & # 178; - 3ay quartic X & # 178; (2x-5) + 4 (5-2x) x & # 179; - 4xy & # 178;
Three questions

3ax & # 178; - 3ay quartic power = 3A (X & # 178; - y ^ 4) = 3A (X-Y & # 178;) (x + Y & # 178;) x & # 178; (2x-5) + 4 (5-2x) = (2x-5) (X & # 178;) = x (x-2y) (x + 2Y)

Let a, a + 1 and a + 2 be the three sides of an obtuse triangle, then the value range of a is______ ．

∵ the three sides a, a + 1, a + 2 of obtuse triangle satisfy the following conditions: a + (a + 1) > A + 2A2 + (a − 1) 2 ＜ (a + 2) 2, that is: a ＞ 12a − 4A − 3 ＞ 3, ∵ a ＞ 1 − 1 ＜ a ＜ 3, so 1 ＜ a ＜ 3, so the answer is: 1 ＜ a ＜ 3

Given the quadratic function y = x ^ 2-x + a (a > 0), when the independent variable x is m, the corresponding function value is less than 0. Then the following conclusion about M-1 is correct
A. Function value light rain 0 B. function value greater than 0 C. function value equal to 0 D. the relationship between function value and 0 is uncertain

If the function is open up and two positive roots, the difference between the two is sqrt (1 / 4-4a). Because a > 0, the absolute value of the difference between the two is 0
Adopt

Given 8 x power = 2,8 y power = 3,8 Z power = 5, find 8 2x-2y + Z power

Original formula = 8 ^ 2x △ 8 ^ 2Y × 8 ^ Z
=(8^x)²÷(8^y)²×8^z
=2²÷3²×5
=20/9

Use pieces to form a hollow square with 16 pieces on each side and one piece on each vertex. How many pieces did Xiao Gang share?

16*4-4=60

The quadratic function y = 3x & # 178; - 2x-1 is transformed into y = a (X-H) &# 178; + K by the collocation method

y=3(x^2-2x/3)-1
=3(x^2-2x/3+1/9-1/9)-1
=3(x-1/3)^2-3/9-1
=3(x-1/3)^2-4/3

Given the inverse scale function y = K / 2x and the first-order function y = 2x-1, where the image of the first-order function passes through (a, b) and (a + 1) (B + k), the analytic expression of the inverse scale function and the intersection coordinates of the two functions are obtained?

From a function passing through two points, we can get b = 2a-1, B + k = 2 (a + 1) - 1, so we can get k = 2 from formula (2) minus formula (1), so the inverse proportion function is y = 1 / x, and the intersection points with the function y = 2x-1 are (1,1) and (- 1 / 2, - 2)

Find the number of factors of y = A1 ^ B1 * A2 ^ B2 * A3 ^ B3, note that A1 ^ B1 represents the B1 power of A1

A1 ^ B1 factor B1 + 1
A2 ^ B2 factor B2 + 1
A3 ^ B3 factor B3 + + 1
(b1+1)(b2+1)(b3+1)

Find the tangent equation of the curve X squared plus 1 / 3 x at point 2 and 4 / 3 Bonus points! Correct answer and high score. It's urgent now! The problem is that I don't know the result of derivation! Great Xia, help!