Factorization, a ^ 4-5a ^ 3 + 6A ^ 2-5A + 1,

Factorization, a ^ 4-5a ^ 3 + 6A ^ 2-5A + 1,


Find its root, that is, a ^ 4-5a ^ 3 + 6A ^ 2-5A + 1 = - 0
Divide left and right by a square
A ^ 2 + 1 / A ^ 2-5 (a + 1 / a) + 6 = 0
Let t = a + 1 / A ^ 2 + 1 / A ^ 2 = T ^ 2-2
So the equation is T ^ 2-2-5t + 6 = 0
t=1 4
And then solve a
Get (a ^ 2-A + 1) (a ^ 2-4a + 1) and that's the result



Factorization a 3-6a 2 + 5A + 12


a^3-6a^2+5a+12
=a^3-6a^2-7a+12a+12
=a(a+1)(a-7)+12(a+1)
=(a+1)(a^2-7a+12)
=(a+1)(a-3)(a-4)



=1 =6 =24 (99!)÷(100!)*1000=?


10



What is the formula of matrix multiplication?


|a11 a12 …… a1n||b11 b12 …… b1k| |a21 a22 …… a2n||b21 b22 …… b2k|=| ..…… .|| ..…… .| |am1 am2 …… amn||bn1 bn2 …… bnk| |a11*b11+a12*b21+…… +a1n*bn1 a11*b12+a12*b22+…… +a1n*bn2 |||...



The train with a mass of 1000 tons starts from the station and moves at a constant speed along the straight track. The distance that the train passes through in 100 seconds is 1000 meters. The known movement resistance is 0.005 times of the vehicle weight. The traction force of the locomotive can be calculated


The train with a mass of 1000 tons starts from the station and moves at a constant speed along the straight track. The distance that the train passes through in 100 seconds is 1000 meters. The known movement resistance is 0.005 times of the vehicle weight. The traction force of the locomotive can be calculated



lim(1/x²-cot²x)


This is the first time that we are going to be able to get 178, and we are going to be in the world of 178; and we are going to be the first-x \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\x + 2x & # 178; sinxcosx) / (4x ^ 3) = [(1 + X



If the largest term in the sequence n (n + 4) (2 / 3) n is the k-th term, then K=
The N after 2 / 3 is to the power of n


It is known from the known conditions that an = n (n + 4) (2 / 3) ^ n should be the maximum
Then the sequence {an} must satisfy an > A (n-1) and an > A (n + 1)
That is n (n + 4) · (2 / 3) ^ n > (n + 1) (n + 5) · (2 / 3) ^ (n + 1)
n(n+4)·(2/3)^n>(n-1)(n+3)·(2/3)^(n-1)
That is, 3 (n & # 178; + 4N) > 2 (n & # 178; + 6N + 5). (1)
2(n²+4²)>3(n²+2²-3) .(2)
The solution (1) is n > 10 or n



This is not absolute?


This is not absolute



Five yuan and fifty cents = how much?


5.5 yuan



We know that (M's Square-1) x's square + (M + n) x + 8 = 0 is a linear equation of one variable with respect to S. his solution is m (1) to find
It is known that (M's Square-1) x's square + (M + n) x + 8 = 0 is a univariate linear equation about S. his solution is m (1) finding the value of the algebraic formula 200 (M + n) (n-2m) - 3M + 5 (2) finding the solution of the equation about y-m | y | = n


The title is wrong, please correct it