Factorization: ① x ^ 3-5X ^ 2-6x ② a ^ 2-B ^ 2-2b-1 reduction: [x - (2x of X + 1)] divided by x ^ 2-2x + 1 of x ^ 2-1 First simplify, then evaluate: (a + b) (a-b) + (a + b) square - 2A square, where a = 3, B = - 1 / 3

Factorization: ① x ^ 3-5X ^ 2-6x ② a ^ 2-B ^ 2-2b-1 reduction: [x - (2x of X + 1)] divided by x ^ 2-2x + 1 of x ^ 2-1 First simplify, then evaluate: (a + b) (a-b) + (a + b) square - 2A square, where a = 3, B = - 1 / 3

Solution (1) x & # 179; - 5x & # 178; - 6x
=x(x²-5x-6)
=x(x-6)(x+1)
②a²-b²-2b-1
=a²-(b²+2b+1)
=a²-(b+1)²
=(a+b+1)(a-b-1)
3.[x-2x/(x+1)]÷(x²-2x+1)/(x²-1)
=[x(x+1)-2x]/(x+1)÷(x-1)²/(x+1)(x-1)
=(x²-x)/(x+1)÷(x-1)/(x+1)
=x(x-1)/(x+1)÷(x-1)/(x+1)
=x
4.：(a+b)(a-b)+(a+b)²-2a²
=a²-b²+a²+2ab+b²-2a²
=2ab
=2×3×(-1/3)
=-2

Can factorization be used for 2x ^ 2 = (x + 5) ^ 2?

Solution, 4x & # 178; = x & # 178; + 10x + 25
The solution is 3x & # 178; - 10x = 25
So I can't

1. The common factor of polynomial a (X-Y) + B (- y + x) - C (X-Y) & sup2 is (_________ )
2.a(x-y)²-3(y-x)=(x-y)(_______ )
3.6(x-y)³+18(y-x)²=6(x-y)²(________ )
4. Factorization before evaluation
18x & sup2; (x-2y) & sup2; - 24xy (2y-x) & sup2; - 6x (2y-x) & sup3;, where x = - 3, y = - 1

1.x-y 2.ax-ay+33.x-y+3 4.18x²(x-2y)²-24xy(2y-x)²-6x(2y-x)³ =(x-2y)²(18x²-24xy+6x(x-2y)) =(x-2y)²(18x²-24xy+6x²-12xy) =(x-2y)²(24x²-36xy) =12x(x-2...

Let e ^ tanx-e ^ X and x ^ n be infinitesimals of the same order when X - > 0, then n = ()

Do you want to take the postgraduate entrance examination?
I think few people will do it!

[1 and 1 / 24 - (3 / 8 + 1 / 6-3 / 4) × 24] / 5

[1 and 1 / 24 - (3 / 8 + 1 / 6-3 / 4) × 24] / 5
=[1 and 1 / 24 - (3 / 8 × 24 + 1 / 6 × 24-3 / 4 × 24)] 5
=[1 and 1 / 24 - (9 + 4-18)] 5
=[25 / 24 + 5] △ 5
=25 / 24 + 5 / 5
=5 / 24 + 1
=1 and 5 / 24

The mathematics and physics in science of the eighth grade winter vacation homework

P36 BDD bisector 9cm (1) proves that ∵ be and CD are two heights of ∵ ABC ∵ BF = CF ∵ EF = Oh ∵ HC = ab ∵ AE = Ao in ∵ AEF and ∵ AOH, EF = ch ∵ 1 = ∵ 2 AE = Ao ∵ AEF are all equal to ∵ AOH ∵ AF = ah P37: DB propagates a small ball and a large moon along a straight line

The possible resultant force of the following two common forces F1 and F2 is? A, F1 = 3, F2 = 3N, B, F1 = 6, F2
Which of the following two common forces F1 and F2 may have a resultant force of 7n?
A,F1=3 F2＝3N B,F1=6 F2=3N CF1＝5n F2＝3n DF1=4n F2=1n

BC

To solve the equation: 70% by X + 55% (120-x) = 120 by 65%. Another question: 5: (2x + 3) = 2: (x-1)

70% x + 55% (120-x) = 120
0.7x+66-0.55x=120
0.7x-0.55x=120-66
0.15x=54
x=360
5：(2X+3)=2：（X-1)
5(x-1)=2(2x+3)
5x-5=4x+6
5x-4x=5+6
x=11

1-2:1-6:1-12:1-20:1 -... - 99 × 100:1?

=1-(1/1×2+1/2×3+…… +1/99-1/100)
=1-(1-1/100)
=1-1+1/100
=1/100

Q: 168 is the sum of the prime numbers of those two numbers, and the one digit number of one of them is 17

91 and 77