Is the negative half power of y = x even or odd

Y = x ^ (- 1 / 2) = 1 / √ X domain x > 0
It's not symmetrical about the origin,
So the negative half power of y = x is a non odd non even function

F (x) = the first - 1 x is less than - 1, the square X of the second X is greater than or equal to - 1, less than or equal to 1, the third 1 x is greater than 1, seek continuity and draw function image
F (x) = the first - 1 x is less than - 1, the square X of the second X is greater than or equal to - 1, less than or equal to 1, the third 1 x is greater than 1, seek continuity and draw function image

In X & lt; - 1, f (x) = & nbsp; - 1 is continuous; in - 1 & lt; X & lt; 1, f (x) = x ^ 2 is continuous; in X & gt; 1, f (x) = 1 is continuous

Two conclusions on the symmetry of function image
1. Let y = f (x) be a function defined on R, then the image of y = f (x-m) and y = f (M-X) (M > 0) are related to each other__ symmetric.
2. On the graph of function y = f (a + x) and function y = f (b-X) symmetric.
The first question is correct
The answer to the second question is (B-A) / 2
If f (x) satisfies that f (a + x) = f (b-X) holds for any x, then the axis of symmetry is (a + b) / 2
Please have a look again!

1.x=0
2.x=(a+b)/2.
∵ y = f (a + x) = f [(a + b) / 2 + (a-b) / 2 + x] = f [(a + b) / 2 + T], where t = (a-b) / 2 + X,
And y = f (b-X) = f [(a + b) / 2 - (a-b) / 2-x] = f [(a + b) / 2 - ((a-b) / 2 + x)] = f [(a + b) / 2-T],
So: the image of function y = f (a + x) and function y = f (b-X) is symmetric with respect to the line x = (a + b) / 2
The answer of 2 is x = (a + b) / 2. It's not x = (B-A) / 2. If the latter, when a = B, the axis of symmetry becomes x = 0, which is obviously wrong. In fact, when a = B, the axis of symmetry is obviously x = a, which is consistent with my answer here

Divide the wire with length of 20 into two sections to form a square and a circle respectively. To minimize the sum of the area of the square and the circle, calculate the circumference of the square

Let the side length of a square be x, and (x / 4) ^ 2 + Pai ((20-x) / 2pai) ^ 2 be the sum of areas. It can be simplified to 100 / PAI + ((PAI + 4) x ^ 2-160x) / 16pai. When the side length is, the area is the smallest

(A-2) x ^ 2 + (2B + 1) xy-x + Y-7 is a polynomial about X, Y. if it does not contain a quadratic term, try to find the value of 3a-8b

Because it doesn't contain quadratic term [if the coefficient of quadratic term is 0, it doesn't contain quadratic term]
So: A-2 = 0
2b+1=0
The solution is a = 2
b=-1/2
So 3a-8b
=3×2-8×（-1/2)
=6+4
=10

There are two kinds of goods: A and B. the profit from selling these two kinds of goods is p (ten thousand yuan) and Q (ten thousand yuan). The relationship between them and the invested capital x (ten thousand yuan) has the empirical formula P = 15x, q = 35x. Now there are thirty thousand yuan invested in running a and B. in order to obtain the maximum profit, what should be the capital investment for a and B respectively? How much profit can we make?

Suppose that the capital investment of a and B is respectively x, (3-x) ten thousand yuan, and the profit is s, then s = 15x + 353 − x, and the square of both sides is sorted out to be x2 + (9-10S) x + 25s2-27 = 0, △ = (9-10S) 2-4 × (25s2-27) ≥ 0, and the solution is s ≤ 189180 = 1.05

1、 If the side length of a square is increased by 5 decimeters, the area will be increased by 125 square decimeters?
Practical problems need formulas,

[(125-5*5)/2]/5=10
The original square is 10 decimeters long,
The area is 100 square decimeters

It is known that it takes time t 0 for sunlight to reach the earth from the sun. The earth's orbit can be seen as a circular orbit approximately. The radius of the earth is about R 0. Try to estimate the ratio of the mass m of the sun to the mass m of the earth

Because the universal gravitation of the sun to the earth provides the centripetal force for the earth to make uniform circular motion around the sun: gmm0r2 = M0 ω 2R = M04 π 2T2R: M = 4 π 2r2gt2 = 4 π 2c3t03gt2, let the radius of the earth be r, then the gravity of the object with mass m 'on the ground is approximately equal to the universal gravitation of the object and the earth, so f ′ = m ′ g, that is: GMM ′ R02 = m ′ G: M = gr02g, so m = 4 π 2c3t03g R02t2 A: the ratio of solar mass m to earth mass m is 4 π 2c3t03gr02t2

Significance of normal stress
Recently, looking at mechanics, I found a silly problem. For example, the linear strain reflects the deformation degree of the member, while the elastic modulus reflects the ability of the material to resist tensile and compressive deformation. What about the normal stress? What effect does it have on the material? What kind of failure does it reflect in engineering practice?

Answer your question: 1. [stress]: the internal force concentration at a certain point on a section of a stressed member. 2. [normal stress]: the stress component perpendicular to the section is called normal stress (including [normal stress]), which is expressed by σ. The so-called [normal stress] is actually a way of applying external load. 3. [shear stress]

Quadratic function problem: the circumference of an isosceles triangle is 10 cm. Find the relationship between its waist length y (CM) and its bottom length x (CM)

From the known relation, 2Y + x = 10
And 2Y > x, which can be divided into two cases as follows:
When the triangle is a non regular triangle, there is / y-x/

Is the negative half power of y = x even or odd