Given the - 2 power of the function y = x, (1) is it an odd function or an even function? (2) what kind of symmetry does its image have? (3) is it in (0, emergency

Given the - 2 power of the function y = x, (1) is it an odd function or an even function? (2) what kind of symmetry does its image have? (3) is it in (0, emergency

(1) Even function (2) has no definition about Y-axis symmetry (3)

Given that f (x) = - 1 / 2 + 1 / X of 2, it is proved that f (x) is an odd function

The domain is x, not 0
f（x）=-1/2+1/（2^x）
f（-x）=-1/2+1/（2^（-x））
f（x）+f（-x）=[-1/2+1/（2^x）]+[-1/2+1/（2^（-x））]=0
So f (x) = - f (- x)
So it's an odd function

If a set of data is known, x1, X2 The average of XN is x0 and the variance is s ^ 2
Then another set of data 3x-2, 3x (small 2) - 2 The average and variance of 3x (small n) - 2 thank you!

(x1+x2+...+xn)/n = x0
[(3x1-2)+(3x2-2)+...+(3xn-2)]/n = 3x0-2
The average is 3x0-2
The variance is 9s ^ 2, which can be deduced from the definition of variance

If the diagonal length of a square is l, then the area of the square is () and the perimeter is ()

If the diagonal length of a square is l, then the area of the square is (L & # / 2) and the perimeter is (2 root sign 2L)

When 0 ＜ x ＜ 6, find the maximum value of 6x-x & #

Mean value theorem:
It is known that x, y ∈ R +, x + y = s, X · y = P
(1) If P is a fixed value, then s has a minimum value if and only if x = y;
(2) If s is a constant, then p has a maximum if and only if x = y
X + (6-x) = 6, which is the fixed value
When 0 ＜ x ＜ 6, 6x-x & # 178; = x (6-x)
When x = 6-x, i.e. x = 3, the maximum value is 9

Find ∫ (arcsinx) ^ 2DX =?

Let arcsinx = t x = sint ∫ (arcsinx) ^ 2DX = ∫ T ^ 2costdt = ∫ T ^ 2dsint = T ^ 2sint-2 ∫ tsintdt = T ^ 2sint + 2 ∫ tdcost = T ^ 2sint + 2 (tcost - ∫ costdt) = T ^ 2sint + 2 (tcost Sint) ∫ (arcsinx) ^ 2DX = x (arcsinx) ^ 2 + 2 (arcsinxcos (arcsinx

Four identical rectangles are put together to form a large square whose hollow part is a small square. It is known that the side length of a large square is 10 cm

What do you want? Do you know the side length of the small square inside? It's easy to do if you know
The side length of the big square is 10 cm, that is to say, it is exactly the same rectangle
L + W = 10 cm
Length width = the side length of the inner small square
In this way, the length and width of the rectangle can be calculated

On the Fifth Grade Evaluation Handbook
In the morning, a few students in the playground, some exercise, some reading, which reminds me of this motto:____________________________ ,________________________________ .
Seeing Zhang Han's anger, the monitor shook his head and read a sentence:_____________________________________ ,___________________________________________ Remind him not to be rude and polite
Correct answer to 60 points! Urgent! Anyway, points are useless

Second, if life deceives you, don't worry or worry. You should be calm when you are sad. Believe it, then happy days will come

The general solution of Y * dy / DX = x * (1-y ^ 2) is

First, separate the variable y / (1-y ^ 2) * dy = x * DX - 0.5 * D (1-y ^ 2) / 1-y ^ 2 = x * DX integral
-0.5 * ln (1-y ^ 2) = 0.5 * x ^ 2 + C Y ^ 2 = 1-e ^ (- x ^ 2-C)

Nine small squares make up a big square. How many rectangles are there in it?

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